Sagemath example

2024-07-15

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When \(a \ne 0\), there are two solutions to \(ax^2 + bx + c = 0\) and they are \[x = {-b \pm \sqrt{b^2-4ac} \over 2a}.\]

SageCell示例

简单计算

print("Hello from SageCell!")

#三角函数图像 plot(sin(x), (x, 0, 2*pi))

交互式计算

@interact def _(a=(1, 10)): print(factorial(a))
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